For 4 points, that is (1/2)3=1/8(1/2)^3 = 1/8(1/2)3=1/8, the same 12.5% we measured earlier. There is one such event for each of the NNN points, so we have NNN events each with probability 1/2N−11/2^{N-1}1/2N−1.
odd positions: 9,7,5,3,1 sum to 25;
，这一点在Line官方版本下载中也有详细论述
https://feedx.net，更多细节参见clash下载 - clash官方网站
for c in typing.Iter[typing.Attrs[K]]。Line官方版本下载是该领域的重要参考